The purpose of split function (table valued function) is to split a delimited value into multiple values based on delimiter and display in tabular form.
Split Function takes two parameters
Let's take an example to split a comma delimited value into multiple values on the basis of delimiter (comma) using split function.
Now let's take another example where you have multiple delimited value stored in a table against an ID and each value needs to split on the basis of delimiter.
We would be using Cross Apply clause in the example.
Split Function takes two parameters
- Delimited Value: The delimited value to be split in multiple values.
- Delimiter: The delimiter like comma, colon, semicolon, pipe etc. on the basis of which delimited value to be split.
CREATE FUNCTION dbo.split( @delimited NVARCHAR(MAX), @delimiter NVARCHAR(100) ) RETURNS @t TABLE (id INT IDENTITY(1,1), val NVARCHAR(MAX)) AS BEGIN DECLARE @xml XML SET @xml = N'<t>' + REPLACE(@delimited,@delimiter,'</t><t>') + '</t>' INSERT INTO @t(val) SELECT r.value('.','varchar(MAX)') as item FROM @xml.nodes('/t') as records(r) RETURN ENDStep wise explanation of split Function
- Converting the delimited value into XML using replace function, where all delimiters are getting replaced with tag to make it as XML and assigning the same to XML Variable
- Reading the Node from XML variable and storing the values in table variable @t.
- Returning the table variable @t
Let's take an example to split a comma delimited value into multiple values on the basis of delimiter (comma) using split function.
SELECT * FROM dbo.split('val1,val2,val3', ',')
Now let's take another example where you have multiple delimited value stored in a table against an ID and each value needs to split on the basis of delimiter.
We would be using Cross Apply clause in the example.
DECLARE @TAB TABLE( id int, list varchar(100) ) INSERT INTO @TAB SELECT 1, 'apple;banana;grapes;orange' UNION ALL SELECT 2, 'potato;onion;carrot;brinjal' SELECT * FROM @TAB SELECT t.id, s.val FROM @TAB t CROSS APPLY dbo.split(t.list, ';') sRESULT
8 comments:
Write Commentsits really helpful.
ReplyDeleteHi
ReplyDeleteFound this article helpful in resolving imports from old system, what i need to know is if you can use something similar on multiple columns instead of just one
Use split function for each list and join on id
ReplyDeleteHi one more question, I have a column with values "21:20~21:28~21:28~21:40~21:40~21:40~21:42" ie tilde delim, that I now need to split into separate columns for each value. Suggestions?
ReplyDeleteThank you, Louis...
ReplyDeleteThan You, was hoping not to
ReplyDeleteHi,
ReplyDeleteThis is only one value for the column. I guess, there would be many different values. How would
you generate columns for each value?
However after using split function you can use dynamic pivot to generate columns.
Refer http://bit.ly/12pEG93 for dynamic pivot.
Hi, thank You, it seems to be the accepted way of doing it, very much appreciated
ReplyDelete